\[{\text{Вычислите: }}\frac{1}{{\sin {{20}^ \circ }}} - \frac{1}{{\operatorname{tg} {{40}^ \circ }}}.\]
\[\begin{array}{l}
\frac{1}{{\sin {{20}^ \circ }}} - \frac{1}{{\operatorname{tg} {{40}^ \circ }}} = \frac{1}{{\sin {{20}^ \circ }}} - \frac{{\cos {{40}^ \circ }}}{{\sin {{40}^ \circ }}} = \frac{{2\cos {{20}^ \circ } - \cos {{40}^ \circ }}}{{\sin {{40}^ \circ }}} = \hfill \\
\frac{{2\cos {{20}^ \circ } - 2\cos {{60}^ \circ }\cos {{40}^ \circ }}}{{\sin {{40}^ \circ }}} = \frac{{2\cos {{20}^ \circ } - \cos {{100}^ \circ } - \cos {{20}^ \circ }}}{{\sin {{40}^ \circ }}} = \hfill \\
\frac{{\cos {{20}^ \circ } - \cos {{100}^ \circ }}}{{\sin {{40}^ \circ }}} = \frac{{2\sin {{60}^ \circ }\sin {{40}^ \circ }}}{{\sin {{40}^ \circ }}} = \sqrt 3 \hfill \\
\end{array}\]
\[\sqrt 3 \]