№2127
\[{\text{Найдите }}y \in \mathbb{N}.\]
$$\frac{1}{{\sqrt[3]{{{{\cos }^2}\frac{{2\pi }}{9}}}}} + \frac{1}{{\sqrt[3]{{{{\cos }^2}\frac{{4\pi }}{9}}}}} + \frac{1}{{\sqrt[3]{{{{\cos }^2}\frac{{8\pi }}{9}}}}} = \sqrt[3]{{\frac{{y\left( {\sqrt[3]{9} - 1} \right)}}{{\sqrt[3]{9} - 2}}}}$$
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