\[\begin{array}{l}
{\text{Решите уравнение:}} \hfill \\
\sqrt {{x^2} + {{\left( {1 - {x^3}} \right)}^2}} + \sqrt {{{\left( {x - 3} \right)}^2} + {{\left( {1 - {x^3}} \right)}^2}} = 3. \hfill \\
\end{array} \]
\[\begin{array}{l}
{\text{Если }}1 - {x^3} \ne 0,{\text{ то }} \hfill \\
\sqrt {{x^2} + {{\left( {1 - {x^3}} \right)}^2}} + \sqrt {{{\left( {x - 3} \right)}^2} + {{\left( {1 - {x^3}} \right)}^2}} > \sqrt {{x^2}} + \sqrt {{{\left( {x - 3} \right)}^2}} = \hfill \\
\left| x \right| + \left| {x - 3} \right| \geqslant 3,{\text{ т}}{\text{.е}}{\text{. решений нет}}{\text{.}} \hfill \\
\end{array} \]
\[x = 1\]
