№2068
\[\begin{array}{l}
{\text{Докажите}}{\text{, что}} \hfill \\
{\left( {\frac{a}{{a - 1}}} \right)^{\frac{{b - 1}}{b}}} = 1 + \frac{{1 + \frac{{1 + \frac{{...}}{{{a_3}}}}}{{{a_2}}}}}{{{a_1}}}, \hfill \\
{\text{где }}{a_k} = a + \frac{a}{{b \cdot k - 1}},{\text{ }}a,b > 1. \hfill \\
\end{array} \]
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Igore
989 days ago
\[... = {\text{hypergeom}}\left( {\left[ {\frac{1}{b} - 1} \right],\left[ {} \right],\frac{1}{a}} \right)\]
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