$%\left( {\sqrt 5 - \sqrt 2 } \right){3^x} - \frac{{{3^{4 - x}}}}{{\sqrt 5 + \sqrt 2 }} - \left( {\sqrt 6 - \sqrt 2 } \right){2^{1 - 2x}} + \frac{{{2^{2x - 3}}}}{{\sqrt 6 + \sqrt 2 }} = 0$%